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Old Dec 4, 2011 | 03:06 PM
  #18411  
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Ja alltså.... snön får fan dyka upp snart alltså. Kommer det ingen innan jag åker tar jag 5 dagar i Alperna på vägen hem.
 
Old Dec 4, 2011 | 03:13 PM
  #18412  
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Originally Posted by strebo
Ja alltså.... snön får fan dyka upp snart alltså. Kommer det ingen innan jag åker tar jag 5 dagar i Alperna på vägen hem.
Ja då får du nog klättra upp på en glaciär, för det finns ingen snö i alperna heller.
 
Old Dec 4, 2011 | 03:16 PM
  #18413  
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Originally Posted by jox
Ja då får du nog klättra upp på en glaciär, för det finns ingen snö i alperna heller.
Inga problem. Varför tror du jag tränar?
 
Old Dec 4, 2011 | 03:28 PM
  #18414  
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Jag är ju en stark motståndare mot snö och har så varit i många år. Men i år har någonting ändrats. Om det är att jag är sugen på att sladda runt Lund med en vettig bakhjulsdriven bil eller om det är julkänsla låter jag vara oskrivet men jag hoppas innerligt på en vit jul.
 
Old Dec 4, 2011 | 03:42 PM
  #18415  
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Originally Posted by Dave S
Jag är ju en stark motståndare mot snö och har så varit i många år. Men i år har någonting ändrats. Om det är att jag är sugen på att sladda runt Lund med en vettig bakhjulsdriven bil eller om det är julkänsla låter jag vara oskrivet men jag hoppas innerligt på en vit jul.
Snö kan vara ett helvete också. Förra året föll hur många grenar som helst från träd som inte pallade trycket ovanifrån. En gren kapade backspegel på vår bil....





Tur i oturen kanske Ingen avled i alla fall!
 

Last edited by SHH; Dec 4, 2011 at 03:46 PM.
Old Dec 4, 2011 | 04:02 PM
  #18416  
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Bara jag som tycker att Analzillas bidrag om att han skinkat på en brud högst motbjudande?
 
Old Dec 4, 2011 | 04:21 PM
  #18417  
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Någon av er snubbar som är vass på matte? Behöver hjälp med följande uppgifter

1. Värdet, y kr, på en bil, t år efter inköpet ges av sambandet y = 180000*0,94^t
Beräkna hur snabbt bilens värde ändras exakt 5 år efter inköpet.

2. I vilka punkter har kurvan y = x^3/3 - 2x^2 horisontella tangenter?

3. En tangent dras till kurvan y = 2e^0.5x - 2x vid x =0. Bestäm tangentens ekvation.
 
Old Dec 4, 2011 | 04:46 PM
  #18418  
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Originally Posted by Blackout
Någon av er snubbar som är vass på matte? Behöver hjälp med följande uppgifter

1. Värdet, y kr, på en bil, t år efter inköpet ges av sambandet y = 180000*0,94^t
Beräkna hur snabbt bilens värde ändras exakt 5 år efter inköpet.

2. I vilka punkter har kurvan y = x^3/3 - 2x^2 horisontella tangenter?

3. En tangent dras till kurvan y = 2e^0.5x - 2x vid x =0. Bestäm tangentens ekvation.
Ska göra de andra också. Började med #2 av någon anledning.

 
Old Dec 4, 2011 | 04:55 PM
  #18419  
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Ohh shit, kudos för att du tar dig tid såhär sent en söndagkväll!
Kan inte ge rep av någon anledning annars hade du haft massor guld nu..

/Filipo
 
Old Dec 4, 2011 | 05:07 PM
  #18420  
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Originally Posted by Blackout
Ohh shit, kudos för att du tar dig tid såhär sent en söndagkväll!
Kan inte ge rep av någon anledning annars hade du haft massor guld nu..

/Filipo
Helt lugnt. Min pedagogik är dock inte den bästa så här sent



Kan dubbelkolla här:

http://m.wolframalpha.com/input/?i=p...2+-+x&x=3&y=13

I första frågan ska du bara räkna ut y'(5)
 

Last edited by SHH; Dec 4, 2011 at 05:23 PM.

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